contoh soal mekanika fluida dan penyelesaiannya

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kumpulan contoh soal mekflu
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  MEKANIKA FLUIDA TUGAS BESAR “aliran mantap melalui sistem pipa ” DIBUAT OLEH Dina aulia fitriHasmiyatiLili purwatiNeneng sari nengsi KELAS BTEKNIK SIIL S!FAKULTAS TEKNIK UNI E#SITAS #IAU $%!&'$%!( Soal 2 (Dina Aulia Fitri) Hitung debit pada pipa – pipa di bawah ini :  Penyelesaian : zA = elevasi A - elevasi D = 100 m – 80 m = 20 mz = elevasi  - elevasi D = 8! m – 80 m = ! m z = elevaasi - elevasi D = #2 m – 80 m = 12 m Pemisalan 1  Dianggap elevasi ga$is te%anan di & sama dengan elevasi mu%a ai$ '  (adi ali$an %e atau da$i %)lam  = 0 ' he = elevasi ga$is te%anan dititi% & – elevasi D = 8! m – 80 m = ! m  h* 1 = 20 m – ! m = 1! mh* 1  = 8 flgπ  2  D 5 + , 1 2 1!  = 8  x 0,03  x 3009,81  x 3,14 2  x 0,45 5 + , 1 2 , 1 2 = 0./18, 1 = 00#8 m . s  h* .  = z - h& = 12 m – ! m = / mh* .  = 8 flgπ  2  D 5 + , . 2 /  = 8  x 0,027  x 9009,81  x 3,14 2  x 0,55 5 + , . 2 , . 2  = 01/!., .  = 018/ m . s   h*   = h& = ! mh*    = 8 flgπ  2  D 5 + ,  2 !  = 8  x 0,05  x 5009,81  x 3,14 2  x 0,6 5 + ,  2 ,  2  = 01880,  = 0.. m . s3, = 4,1 5 ,26 – 4,. 5 ,6 = 400#85 06 – 4018/ 5 0..6 = 00#8 – 08!2. = - 022! m . s 7 0  (adi pe$samaan %)ntinuitas belum te$penuhi Pemisalan 2  Dianggap elevasi ga$is te%anan di & = #0 m he = #0 – elevasi D = #0 m – 80 m = 10 m  h* 1 = 20 m – 10 m = 10 mh* 1  = 8 flgπ  2  D 5 + , 1 2 10  = 8  x 0,03  x 3009,81  x 3,14 2  x 0,45 5 + , 1 2 , 1 2  = 02/#, 1  = 0#/8 m . s  h* 2 = h& - z = 10 m – ! m = ! mh* 2  = 8 flgπ  2  D 5 + , . 2 !  = 8  x 0,025  x 3509,81  x 3,14 2  x 0,45 5 + , 2 2 , 2 2  = 012/!  , 2  = 0.!/1 m . s  h* .  = z - h& = / m - ! m = 2mh*  .  = 8 flgπ  2  D 5 + , . 2 2  = 8  x 0,027  x 9009,81  x 3,14 2  x 0,55 5 + , . 2 , . 2  = 00!01, . = 022.8 m . s  h*   = h& = 10mh*    = 8 flgπ  2  D 5 + ,  2 10  = 8  x 0,05  x 5009,81  x 3,14 2  x 0,6 5 + ,  2 ,  2  = 0./1,  = 01.. m . s3, = 4,1 5 ,26 – 4,. 5 ,6 = 40#/85 0.!/16 – 4022.8 5 01..6 = 08!# – 08./1 = 001/8 m . s  0  (adi pe$samaan %)ntinuitas te$penuhi Soal 3 (Hasmiyati) Air dari kolom B ke kolam A melalui pipa 1 (Diameter = 250 mm, panjang = 500 m) dan pipa 2 (Diameter = 300 mm, panjang 500 m) menuju pipa 3 (Diamater = 200 mm, panjang = 750 m).  pipa yang digunakan adala pipa !e i tuang. #arila de!it ma ing$ma ing pipa.
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